16. Calculate the time it takes a 0.5 kW appliance to transfer 1.3 kJ of energy (1dp)

Sure, here's how you can calculate it:

Step 1: First, we need to convert the power of the appliance from kilowatts (kW) to joules per second (J/s) because the energy is given in joules (J). We know that 1 kW = 1000 J/s. So, 0.5 kW = 0.5 * 1000 = 500 J/s.

Step 2: Next, we need to convert the energy from kilojoules (kJ) to joules (J). We know that 1 kJ = 1000 J. So, 1.3 kJ = 1.3 * 1000 = 1300 J.

Step 3: Now, we can calculate the time it takes for the appliance to transfer this energy. We know that power = energy / time. So, rearranging for time, we get time = energy / power = 1300 J / 500 J/s = 2.6 seconds.

So, it takes approximately 2.6 seconds for a 0.5 kW appliance to transfer 1.3 kJ of energy.

First, we need to understand that power (P) is the rate of energy (E) transfer, which can be calculated using the formula:

P = E / t

Where: P is power in kilowatts (kW), E is energy in kilojoules (kJ), and t is time in seconds (s).

We can rearrange this formula to solve for time:

t = E / P

Given in the problem, we have: P = 0.5 kW and E = 1.3 kJ.

Substituting these values into the formula gives:

t = 1.3 kJ / 0.5 kW

But we need to be careful with the units. In this formula, the power should be in kW and the energy should be in kJ. So, we don't need to convert anything.

t = 1.3 / 0.5 = 2.6 seconds

So, it takes 2.6 seconds for a 0.5 kW appliance to transfer 1.3 kJ of energy.