A 0.040 M HCl solution is measured in the laboratory and has an osmotic pressure of 1.9 atm. What is the estimated osmotic pressure of gastric acid (approximated as 0.10 M HCl) under the same conditions?A.0.19 atmB.0.40 atmC.2.4 atmD.4.8 atm
Question
A 0.040 M HCl solution is measured in the laboratory and has an osmotic pressure of 1.9 atm. What is the estimated osmotic pressure of gastric acid (approximated as 0.10 M HCl) under the same conditions?A.0.19 atmB.0.40 atmC.2.4 atmD.4.8 atm
Solution
The osmotic pressure of a solution is directly proportional to its molarity. This means that if you double the molarity of a solution, you will also double its osmotic pressure.
In this case, the molarity of the gastric acid (0.10 M) is 2.5 times greater than the molarity of the 0.040 M HCl solution. Therefore, the osmotic pressure of the gastric acid will also be 2.5 times greater than the osmotic pressure of the 0.040 M HCl solution.
So, to find the osmotic pressure of the gastric acid, you multiply the osmotic pressure of the 0.040 M HCl solution (1.9 atm) by 2.5:
1.9 atm * 2.5 = 4.75 atm
The answer closest to this is 4.8 atm, so the correct answer is D. 4.8 atm.
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