What will be the output of following Python code snippet?for i in range(0 , -2 , -1): print(i)0,-10, -1, -1-1, -2Error

The output of the given Python code snippet will be:

0 -1

Here's the step by step explanation:

1. The range() function in Python is used to generate a sequence of numbers over time. It takes three parameters - start, stop, and step. In this case, start is 0, stop is -2, and step is -1.

2. The for loop is used to iterate over the sequence generated by the range() function. In each iteration, the value of i is printed.

3. In the first iteration, i is 0. So, 0 is printed.

4. In the next iteration, i is decreased by 1 (because the step is -1), so i becomes -1. So, -1 is printed.

5. Now, i should be decreased by 1 again to become -2. But -2 is the stop value in the range() function, which means the loop should stop before i becomes -2. So, the loop ends here.

Therefore, the output of the code is 0 and -1.

The output of the given Python code snippet will be:

0 -1

Explanation: The range() function in Python starts at 0 and ends before -2, decrementing by -1 at each step. So, it first prints 0, then decrements by 1 and prints -1. After this, the next value would be -2, but since the range ends before -2, the loop terminates.

The output of the given Python code snippet will be:

0 -1

Here's the step by step explanation:

1. The range() function in Python generates a sequence of numbers starting from the first parameter (0 in this case), up to but not including the second parameter (-2 in this case), incrementing by the third parameter (-1 in this case).

2. The for loop iterates over this sequence of numbers.

3. In the first iteration, i is 0, so 0 is printed.

4. In the second iteration, i is decremented by 1 (because the step is -1), so -1 is printed.

5. Now i would be -2, but -2 is the stop parameter for the range() function, so the loop ends.

Therefore, the output is:

0 -1