Consider two sorting algorithms, Algorithm A with a time complexity of O(n^2) and Algorithm B with a time complexity of O(n log n). Which algorithm is likely to perform better for moderately large input sizes, and why?a.Algorithm B, because it has a lower time complexity.b.Algorithm A, because it has a lower time complexity.c.Algorithm A, because it has a higher time complexity.d.Algorithm B, because it has a higher time complexity.
Question
Consider two sorting algorithms, Algorithm A with a time complexity of O(n^2) and Algorithm B with a time complexity of O(n log n). Which algorithm is likely to perform better for moderately large input sizes, and why?a.Algorithm B, because it has a lower time complexity.b.Algorithm A, because it has a lower time complexity.c.Algorithm A, because it has a higher time complexity.d.Algorithm B, because it has a higher time complexity.
Solution
The correct answer is a. Algorithm B, because it has a lower time complexity.
The time complexity of an algorithm quantifies the amount of time taken by an algorithm to run, as a function of the length of the input. It is used in computer science to describe the performance or complexity of an algorithm.
Algorithm B has a time complexity of O(n log n), which is better than Algorithm A's time complexity of O(n^2) for large input sizes. This is because as the input size increases, the time taken by Algorithm A will increase quadratically, while the time taken by Algorithm B will increase logarithmically. Therefore, for moderately large input sizes, Algorithm B is likely
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