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Select the correct answerTen years ago, P was half of Q's age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages?Options40453530

Question

Select the correct answerTen years ago, P was half of Q's age. If the ratio of their present ages is 3 : 4, what will be the total of their present ages?Options40453530

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Solution 1

Let's solve this step by step:

Step 1: Let's assume the present age of P is 3x and the present age of Q is 4x.

Step 2: According to the problem, ten years ago, P was half of Q's age. So, we can write this as: 3x - 10 = 1/2 (4x - 10).

Step 3: Solving the above equation, we get: 6x - 20 = 4x - 10.

Step 4: Simplifying it further, we get: 2x = 10.

Step 5: Solving for x, we get: x = 5.

Step 6: Substituting x = 5 in 3x and 4x, we get the present ages of P and Q as 15 and 20 respectively.

Step 7: The total of their present ages is 15 + 20 = 35.

So, the correct answer is 35.

This problem has been solved

Solution 2

Let's solve this step by step:

Step 1: Let's assume the present age of P is 3x and the present age of Q is 4x.

Step 2: According to the problem, ten years ago, P was half of Q's age. So, we can write this as: 3x - 10 = 1/2 (4x - 10).

Step 3: Solving the above equation, we get: 6x - 20 = 4x - 10.

Step 4: Simplifying it further, we get: 2x = 10.

Step 5: Solving for x, we get: x = 5.

Step 6: Substituting x = 5 in 3x and 4x, we get the present ages of P and Q as 15 and 20 respectively.

Step 7: The total of their present ages is 15 + 20 = 35.

So, the correct answer is 35.

This problem has been solved

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