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For the following unbalanced reaction, what should be the coefficient in front of the product BaSO4 once the equation is completely balanced? BaCl2  +    Fe2(SO4)3   -->    FeCl3  + BaSO4

Question

For the following unbalanced reaction, what should be the coefficient in front of the product BaSO4 once the equation is completely balanced? BaCl2  +    Fe2(SO4)3   -->    FeCl3  + BaSO4

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Solution

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.

  1. Start with the most complex molecule, which is Fe2(SO4)3 in this case. There are 2 Fe atoms and 3 SO4 groups. To balance the Fe atoms, put a 2 in front of FeCl3. Now, the equation looks like this: BaCl2 + Fe2(SO4)3 --> 2FeCl3 + BaSO4.

  2. Next, balance the SO4 groups. There are 3 SO4 groups in Fe2(SO4)3, so put a 3 in front of BaSO4. Now, the equation looks like this: BaCl2 + Fe2(SO4)3 --> 2FeCl3 + 3BaSO4.

  3. Now, balance the Ba atoms. There are 3 Ba atoms on the right side, so put a 3 in front of BaCl2. Now, the equation looks like this: 3BaCl2 + Fe2(SO4)3 --> 2FeCl3 + 3BaSO4.

  4. Finally, balance the Cl atoms. There are 6 Cl atoms on the left side, so put a 6 in front of FeCl3. Now, the equation looks like this: 3BaCl2 + Fe2(SO4)3 --> 6FeCl3 + 3BaSO4.

So, the coefficient in front of the product BaSO4 once the equation is completely balanced is 3.

This problem has been solved

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