For the following unbalanced reaction, what should be the coefficient in front of the product BaSO4 once the equation is completely balanced? BaCl2 + Fe2(SO4)3 --> FeCl3 + BaSO4
Question
For the following unbalanced reaction, what should be the coefficient in front of the product BaSO4 once the equation is completely balanced? BaCl2 + Fe2(SO4)3 --> FeCl3 + BaSO4
Solution
To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.
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Start with the most complex molecule, which is Fe2(SO4)3 in this case. There are 2 Fe atoms and 3 SO4 groups. To balance the Fe atoms, put a 2 in front of FeCl3. Now, the equation looks like this: BaCl2 + Fe2(SO4)3 --> 2FeCl3 + BaSO4.
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Next, balance the SO4 groups. There are 3 SO4 groups in Fe2(SO4)3, so put a 3 in front of BaSO4. Now, the equation looks like this: BaCl2 + Fe2(SO4)3 --> 2FeCl3 + 3BaSO4.
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Now, balance the Ba atoms. There are 3 Ba atoms on the right side, so put a 3 in front of BaCl2. Now, the equation looks like this: 3BaCl2 + Fe2(SO4)3 --> 2FeCl3 + 3BaSO4.
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Finally, balance the Cl atoms. There are 6 Cl atoms on the left side, so put a 6 in front of FeCl3. Now, the equation looks like this: 3BaCl2 + Fe2(SO4)3 --> 6FeCl3 + 3BaSO4.
So, the coefficient in front of the product BaSO4 once the equation is completely balanced is 3.
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