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An ideal gas at a given state expands to a fixed final volume first at constant pressure and then at constant temperature. In which case is the work done greater?Group of answer choicesConstant volumeConstant pressureNone of themConstant temperatureNext

Question

An ideal gas at a given state expands to a fixed final volume first at constant pressure and then at constant temperature. In which case is the work done greater?Group of answer choicesConstant volumeConstant pressureNone of themConstant temperatureNext

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Solution

The work done is greater in the case of constant pressure. This is because work done (W) by a gas can be calculated using the formula W=PΔV, where P is the pressure and ΔV is the change in volume. In the case of constant pressure, as the volume increases, the work done also increases. In the case of constant temperature, the pressure decreases as the volume increases, resulting in less work done. Therefore, the work done is greater at constant pressure.

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