(i) Zinc reacts with silver nitrate to produce zinc nitrate and silver.(ii) Potassium iodide reacts with lead nitrate to produce potassium nitrate and lead iodide
Question
(i) Zinc reacts with silver nitrate to produce zinc nitrate and silver.(ii) Potassium iodide reacts with lead nitrate to produce potassium nitrate and lead iodide
Solution
(i) When zinc (Zn) reacts with silver nitrate (AgNO3), it displaces the silver (Ag) from the silver nitrate, resulting in the formation of zinc nitrate (Zn(NO3)2) and silver. This is a displacement reaction. The balanced chemical equation for this reaction is:
Zn + 2AgNO3 → Zn(NO3)2 + 2Ag
(ii) Similarly, when potassium iodide (KI) reacts with lead nitrate (Pb(NO3)2), it results in the formation of potassium nitrate (KNO3) and lead iodide (PbI2). This is a double displacement reaction. The balanced chemical equation for this reaction is:
2KI + Pb(NO3)2 → 2KNO3 + PbI2
In both reactions, the reactants exchange ions to form new compounds.
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