Assuming the existence of two integers, begin and end, that hold some value; declare a variable named sumRange that holds the sum of all integers in the range [begin, end]. For example, if begin = 3 and end = 5, sumRange should be 3+4+5 = 12if begin = 8 and end = 8, sumRange should be 8if begin = 10 and end is ANY VALUE LESS THAN 10, sumRange should be 0Following is buggy code. Click on "Check" and study the error. Then read the problem statement again carefully, and identify the issue based on the error message.For example:Test Resultint begin = 10, end = 12;for begin = 10 and end = 12, sumRange = 33int begin = 50, end = 10;for begin = 50 and end = 10, sumRange = 0int begin = 120, end = 120;for begin = 120 and end = 120, sumRange = 120
Question
Assuming the existence of two integers, begin and end, that hold some value; declare a variable named sumRange that holds the sum of all integers in the range [begin, end]. For example, if begin = 3 and end = 5, sumRange should be 3+4+5 = 12if begin = 8 and end = 8, sumRange should be 8if begin = 10 and end is ANY VALUE LESS THAN 10, sumRange should be 0Following is buggy code. Click on "Check" and study the error. Then read the problem statement again carefully, and identify the issue based on the error message.For example:Test Resultint begin = 10, end = 12;for begin = 10 and end = 12, sumRange = 33int begin = 50, end = 10;for begin = 50 and end = 10, sumRange = 0int begin = 120, end = 120;for begin = 120 and end = 120, sumRange = 120
Solution
The problem statement is not clear about what the issue is. However, based on the examples given, it seems like the code is not correctly calculating the sum of all integers in the range [begin, end].
Here's how you can solve this problem:
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Declare a variable named sumRange and initialize it to 0. This variable will hold the sum of all integers in the range [begin, end].
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Use a for loop to iterate over all integers in the range [begin, end]. In each iteration, add the current integer to sumRange.
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After the loop, sumRange will hold the sum of all integers in the range [begin, end].
Here's the corrected code:
int begin = 10, end = 12;
int sumRange = 0;
if (begin <= end) {
for (int i = begin; i <= end; i++) {
sumRange += i;
}
}
This code first checks if begin is less than or equal to end. If it is, it uses a for loop to iterate over all integers in the range [begin, end] and adds each integer to sumRange. If begin is greater than end, it skips the loop and sumRange remains 0.
Similar Questions
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