To make 71.9 mL of a 0.405 M KCl solution, what mass of KCl (molar mass = 74.55 g mol-1) is required? 420.g420.𝑔 2.17g2.17𝑔 0.0291g0.0291𝑔 5.63g5.63𝑔 0.391g0.391𝑔
Question
To make 71.9 mL of a 0.405 M KCl solution, what mass of KCl (molar mass = 74.55 g mol-1) is required? 420.g420.𝑔 2.17g2.17𝑔 0.0291g0.0291𝑔 5.63g5.63𝑔 0.391g0.391𝑔
Solution
To find the mass of KCl required, we first need to find the number of moles of KCl needed. We can do this using the formula:
Molarity (M) = moles of solute / volume of solution in liters
Rearranging the formula to find moles gives us:
moles of solute = Molarity (M) * volume of solution in liters
Substituting the given values:
moles of KCl = 0.405 M * 71.9 mL * (1 L / 1000 mL) = 0.0291 moles
Next, we convert moles of KCl to grams using the molar mass of KCl:
mass of KCl = moles of KCl * molar mass of KCl
Substituting the values:
mass of KCl = 0.0291 moles * 74.55 g/mol = 2.17 g
So, 2.17 g of KCl is required to make 71.9 mL of a 0.405 M KCl solution.
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