What will be the output of the following Python code?l=[1, 0, 2, 0, 'hello', '', []]print(list(filter(bool, l)))Options[1, 2, ‘hello’][1, 0, 2, 0, ‘hello’, ”, [ ]]Error[1, 0, 2, ‘hello’, ”, [ ]]

The output of the given Python code will be [1, 2, 'hello'].

Here's the step by step explanation:

1. The given list 'l' contains various elements - integers, strings, and an empty list.

2. The built-in function 'filter()' in Python takes in two arguments: a function and a list. It offers an elegant way to filter out all the elements of a sequence. For each element in the iterable, 'filter()' applies the function (in this case, 'bool()') and returns only the elements for which the function returns 'True'.

3. The 'bool()' function converts a value to Boolean (True or False) using the standard truth testing procedure. In Python, the following values are considered falsey (i.e., they evaluate to False in a Boolean context): None, False, zero of any numeric type (0, 0.0, 0j, etc.), any empty sequence (e.g., '', (), []), and a few others. All other values are considered truthy (i.e., they evaluate to True in a Boolean context).

4. So, when 'filter(bool, l)' is executed, it applies 'bool()' to each element of 'l'. The elements 0, '', and [] are falsey, so they are filtered out. The elements 1, 2, and 'hello' are truthy, so they are included in the output.

5. 'list(filter(bool, l))' converts the filter object returned by 'filter()' to a list.

6. Therefore, the output of the code is [1, 2, 'hello'].