What will be the output of the following Python code?s = [[m, m + 1, m + 2] for m in range(0, 3)]print(s)Options[0, 1, 2, 1, 2, 3, 2, 3, 4][[0, 1, 2], [1, 2, 3], [2, 3, 4]][[1, 2, 3], [4, 5, 6], [7, 8, 9]][1, 2, 3, 4, 5, 6, 7, 8, 9]
Question
What will be the output of the following Python code?s = [[m, m + 1, m + 2] for m in range(0, 3)]print(s)Options[0, 1, 2, 1, 2, 3, 2, 3, 4][[0, 1, 2], [1, 2, 3], [2, 3, 4]][[1, 2, 3], [4, 5, 6], [7, 8, 9]][1, 2, 3, 4, 5, 6, 7, 8, 9]
Solution
The output of the Python code will be [[0, 1, 2], [1, 2, 3], [2, 3, 4]]. This is because the code is using a list comprehension to create a list of lists. The outer list comprehension is iterating over the range from 0 to 2 (inclusive), and for each number 'm' in this range, it is creating a new list [m, m + 1, m + 2]. So for m = 0, it creates the list [0, 1, 2], for m = 1, it creates the list [1, 2, 3], and for m = 2, it creates the list [2, 3, 4]. These lists are then collected into the outer list, resulting in the final output.
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