2NaOH (aq) +H 2 SO 4 (aq) →Na 2 SO 4 (aq) +2H 2 O (l) 2, N, a, O, H, start subscript, left parenthesis, a, q, right parenthesis, end subscript, plus, H, start subscript, 2, end subscript, S, O, start subscript, 4, end subscript, start subscript, left parenthesis, a, q, right parenthesis, end subscript, right arrow, N, a, start subscript, 2, end subscript, S, O, start subscript, 4, end subscript, start subscript, left parenthesis, a, q, right parenthesis, end subscript, plus, 2, H, start subscript, 2, end subscript, O, start subscript, left parenthesis, l, right parenthesis, end subscriptHow many moles of Na2SO4 will be produced from 72.0g of NaOH, assuming H2SO4 is available in excess?
Question
2NaOH (aq) +H 2 SO 4 (aq) →Na 2 SO 4 (aq) +2H 2 O (l) 2, N, a, O, H, start subscript, left parenthesis, a, q, right parenthesis, end subscript, plus, H, start subscript, 2, end subscript, S, O, start subscript, 4, end subscript, start subscript, left parenthesis, a, q, right parenthesis, end subscript, right arrow, N, a, start subscript, 2, end subscript, S, O, start subscript, 4, end subscript, start subscript, left parenthesis, a, q, right parenthesis, end subscript, plus, 2, H, start subscript, 2, end subscript, O, start subscript, left parenthesis, l, right parenthesis, end subscriptHow many moles of Na2SO4 will be produced from 72.0g of NaOH, assuming H2SO4 is available in excess?
Solution
To solve this problem, we need to follow these steps:
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First, we need to calculate the molar mass of NaOH. The atomic masses of sodium (Na), oxygen (O), and hydrogen (H) are approximately 23 g/mol, 16 g/mol, and 1 g/mol respectively. So, the molar mass of NaOH is 23 + 16 + 1 = 40 g/mol.
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Next, we need to convert the mass of NaOH given in the problem (72.0 g) into moles. We do this by dividing the given mass by the molar mass. So, 72.0 g ÷ 40 g/mol = 1.8 moles of NaOH.
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Now, we look at the balanced chemical equation given in the problem. It tells us that 2 moles of NaOH react to produce 1 mole of Na2SO4. Therefore, 1.8 moles of NaOH will react to produce 1.8 ÷ 2 = 0.9 moles of Na2SO4.
So, assuming that H2SO4 is available in excess, 72.0 g of NaOH will produce 0.9 moles of Na2SO4.
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