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A substance 'A' decomposes by a first order reaction starting initially with [A]=2.00 m and after 200 min,[ A] becomes 0.15 m. For this reaction t1/2 is53.72 min50.49 min48.45 min46.45 min

Question

A substance 'A' decomposes by a first order reaction starting initially with [A]=2.00 m and after 200 min,[ A] becomes 0.15 m. For this reaction t1/2 is53.72 min50.49 min48.45 min46.45 min

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Solution

The half-life (t1/2) of a first order reaction can be calculated using the formula:

t1/2 = 0.693/k

where k is the rate constant. The rate constant can be calculated using the formula for a first order reaction:

ln([A]0/[A]) = kt

where [A]0 is the initial concentration, [A] is the final concentration, and t is the time.

Let's plug in the given values:

ln(2.00/0.15) = k * 200 min

Solving for k gives:

k = ln(2.00/0.15) / 200 min = 0.013 min^-1

Now we can calculate t1/2:

t1/2 = 0.693/0.013 min^-1 = 53.31 min

The closest answer to this is 53.72 min. So, the half-life of the reaction is approximately 53.72 min.

This problem has been solved

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