What is the solution to this system of equations? −3x+5y=21-3𝑥+5𝑦=216x−y=−156𝑥-𝑦=-15 A. (2,27)(2,27) B. (−2,3)(-2,3) C. (2,0)(2,0) D. (−3,−3)
Question
What is the solution to this system of equations? −3x+5y=21-3𝑥+5𝑦=216x−y=−156𝑥-𝑦=-15 A. (2,27)(2,27) B. (−2,3)(-2,3) C. (2,0)(2,0) D. (−3,−3)
Solution
To solve this system of equations, we can use the method of substitution or elimination. Here, I'll use the elimination method.
The system of equations is:
-3x + 5y = 21 6x - y = -15
First, we can multiply the second equation by 5 to make the coefficients of y the same in both equations:
30x - 5y = -75
Now, we have:
-3x + 5y = 21 30x - 5y = -75
We can add these two equations together:
27x = -54
Then, divide both sides by 27 to solve for x:
x = -54 / 27 = -2
Substitute x = -2 into the second equation:
6*(-2) - y = -15 -12 - y = -15 y = 12 - 15 = 3
So, the solution to the system of equations is x = -2 and y = 3. Therefore, the correct answer is B. (-2,3).
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