What is the specific heat capacity of a 10kg object that needs 2.1×10 5 J to have its temperature raised by 5.0 ∘ C?
Question
What is the specific heat capacity of a 10kg object that needs 2.1×10 5 J to have its temperature raised by 5.0 ∘ C?
Solution
The specific heat capacity (c) of an object can be calculated using the formula:
c = Q / (m * ΔT)
where:
- Q is the heat energy supplied to the object (in joules)
- m is the mass of the object (in kilograms)
- ΔT is the change in temperature (in degrees Celsius)
Given:
- Q = 2.1×10^5 J
- m = 10 kg
- ΔT = 5.0 °C
Substitute these values into the formula:
c = 2.1×10^5 J / (10 kg * 5.0 °C) = 4200 J/(kg°C)
So, the specific heat capacity of the object is 4200 J/(kg°C).
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