The sum of squares of all possible values of k, for which area of the region bounded by the parabolas 2y2=kx and ky2=2(y−x) is maximum, is equal to :

If 2x + y + k = 0 is a normal to the parabola y2 = –16x, then find the value of k.

Nonlinear ProgrammingThe largest interval (a, b) of k ∈ R,for which the point (0, 0) is the critical point of the function f(x, y) = x2 + kxy + yans.

The locus of the point (x,y) whose distance from the line y=2x+2 is equal to the distance from (2,0), is a parabola with the length of latus rectum same as that of the parabola y=Kx2, then the value of K is equal toView Question

et |x|2 –2|x| + |k – 3| = 0 be a quadratic equation and ‘k’ being a real number. If x is an integer solution of the given quadratic equation, then what is the largest value of x + k?

Instructions: Given the quadratic function, state whether the parabola opens up or down, and whether it has a maximum or minimum.y=−2x2+8x−3𝑦=−2𝑥2+8𝑥−3The parabola opens and has a vertex of (( ,, )), which is a value.