TWO SIDES OF A TRIANGLE HAVE THE FOLLOWING MEASURES. FIND THE RANGE OF THE POSSIBLE MEASURES FOR THE THIRD SIDE.14, 11, _____*1 point3 < x < 2525 < x < 315 < x < 256, 10, _____*1 point16 < x < 44 < x < 165 < x < 1515, 18, _____*1 point4 < x < 3033 < x < 33 < x < 3311, 20, _____*1 point9 < x < 309 < x < 319 < x < 3247, 21 _____*1 point26 < x < 6827 < x < 6826 < x < 695, 8, _____*1 point3 < x < 143 < x < 133 < x < 126, 9, _____*1 point3 < x < 143 < x < 153 < x < 1617, 19, _____*1 point1 < x < 262 < x < 263 < x < 27
Question
TWO SIDES OF A TRIANGLE HAVE THE FOLLOWING MEASURES. FIND THE RANGE OF THE POSSIBLE MEASURES FOR THE THIRD SIDE.14, 11, _____*1 point3 < x < 2525 < x < 315 < x < 256, 10, _____*1 point16 < x < 44 < x < 165 < x < 1515, 18, _____*1 point4 < x < 3033 < x < 33 < x < 3311, 20, _____*1 point9 < x < 309 < x < 319 < x < 3247, 21 _____*1 point26 < x < 6827 < x < 6826 < x < 695, 8, _____*1 point3 < x < 143 < x < 133 < x < 126, 9, _____*1 point3 < x < 143 < x < 153 < x < 1617, 19, _____*1 point1 < x < 262 < x < 263 < x < 27
Solution
The measures of the third side of a triangle, given the lengths of the other two sides, can be determined using the Triangle Inequality Theorem. This theorem states that the length of any side of a triangle must be less than the sum of the lengths of the other two sides and greater than the difference of the lengths of the other two sides.
-
For sides 14 and 11, the third side must be greater than |14-11|=3 and less than 14+11=25. So, 3 < x < 25.
-
For sides 6 and 10, the third side must be greater than |6-10|=4 and less than 6+10=16. So, 4 < x < 16.
-
For sides 15 and 18, the third side must be greater than |15-18|=3 and less than 15+18=33. So, 3 < x < 33.
-
For sides 11 and 20, the third side must be greater than |11-20|=9 and less than 11+20=31. So, 9 < x < 31.
-
For sides 47 and 21, the third side must be greater than |47-21|=26 and less than 47+21=68. So, 26 < x < 68.
-
For sides 5 and 8, the third side must be greater than |5-8|=3 and less than 5+8=13. So, 3 < x < 13.
-
For sides 6 and 9, the third side must be greater than |6-9|=3 and less than 6+9=15. So, 3 < x < 15.
-
For sides 17 and 19, the third side must be greater than |17-19|=2 and less than 17+19=36. So, 2 < x < 36.
Similar Questions
A triangle has sides measuring 5 inches and 8 inches. If x represents the length in inches of the third side, which inequality gives the range of possible values for x?A.5 ≤ x ≤ 8B.5 < x < 8C.3 < x < 13D.3 ≤ x ≤ 13
The side lengths of a triangle are 8, 17, and x units.178x(The figure above gives only one possible configuration for the triangle.)Determine the possible values of x.Write your answer as an inequality.Use x only once in your inequality.
Find the range for the measure of the third side of a triangle when the measures of the other two sides are 6 ft and 19 ft.
Given the following set of expressions represent the lengths of the sides of a triangle, find the range of possible values of n.If n + 2, 5, and 9 represent the lengths of the sides of a triangle then Blank 1 Question 22 n Blank 2 Question 22 .
Find the range for the measure of the third side of a triangle when the measures of the other two sides are 2 km and 42 km.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.