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GPE = mgh. A rock with a mass of 5 kg is lifted to the top of a cliff that is 30 meters high. What is the gravitational potential energy of the rock at the top of the cliff?*1 pointa) 1500 Jb) 3000 Jc) 4500 Jd) 6000 J

Question

GPE = mgh. A rock with a mass of 5 kg is lifted to the top of a cliff that is 30 meters high. What is the gravitational potential energy of the rock at the top of the cliff?*1 pointa) 1500 Jb) 3000 Jc) 4500 Jd) 6000 J

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Solution

To solve this problem, we need to use the formula for gravitational potential energy (GPE), which is GPE = mgh.

Here, m = mass of the rock = 5 kg g = acceleration due to gravity = 9.8 m/s² (approximately, as it varies slightly depending on where on Earth you are) h = height = 30 m

Substituting these values into the formula, we get:

GPE = 5 kg * 9.8 m/s² * 30 m = 1470 J

However, this is not an option in the multiple choice answers. It's possible that the question assumes g = 10 m/s² for simplicity, which is often done in basic physics problems. If we use g = 10 m/s², we get:

GPE = 5 kg * 10 m/s² * 30 m = 1500 J

So, the answer is a) 1500 J.

This problem has been solved

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