Knowee
Questions
Features
Study Tools

pset 5.1 Consider the linear regression model$$y_{i}=x_{i} \beta+u_{i}$$where the only independent variable $x_{i}$ is determined as$$x_{i}=y_{i} \gamma+v_{i}$$and $V\left(u_{i}\right)=\sigma_{u}^{2}$ and $V\left(v_{i}\right)=\sigma_{v}^{2}, \forall i$. Prove that the OLS estimator of $\beta$ based on the first equation does not converge in probability to $\beta$. (hint: write $x_{i}$ as a function of only $u_{i}$ and $v_{i}$.)

Question

pset 5.1 Consider the linear regression modely_{i}=x_{i} \beta+u_{i}where the only independent variable xix_{i} is determined asx_{i}=y_{i} \gamma+v_{i}and V(ui)=σu2V\left(u_{i}\right)=\sigma_{u}^{2} and V(vi)=σv2,iV\left(v_{i}\right)=\sigma_{v}^{2}, \forall i. Prove that the OLS estimator of β\beta based on the first equation does not converge in probability to β\beta. (hint: write xix_{i} as a function of only uiu_{i} and viv_{i}.)

...expand
🧐 Not the exact question you are looking for?Go ask a question

Solution

To prove that the OLS estimator of β\beta based on the first equation does not converge in probability to β\beta, we need to write xix_i as a function of only uiu_i and viv_i.

From the second equation, we have:

xi=yiγ+vix_i = y_i \gamma + v_i

Substituting this expression for xix_i into the first equation, we get:

yi=(yiγ+vi)β+uiy_i = (y_i \gamma + v_i) \beta + u_i

Expanding and rearranging terms, we have:

yi=yiβγ+βvi+uiy_i = y_i \beta \gamma + \beta v_i + u_i

Now, let's isolate yiy_i on one side:

yiyiβγ=βvi+uiy_i - y_i \beta \gamma = \beta v_i + u_i

Factoring out yiy_i:

yi(1βγ)=βvi+uiy_i(1 - \beta \gamma) = \beta v_i + u_i

Finally, solving for yiy_i:

yi=βvi+ui1βγy_i = \frac{\beta v_i + u_i}{1 - \beta \gamma}

From this expression, we can see that yiy_i is a function of both uiu_i and viv_i. Therefore, the OLS estimator of β\beta based on the first equation does not converge in probability to β\beta.

This problem has been solved

Similar Questions

pset 3.3 Consider the regression model$$y_{i}=\boldsymbol{x}_{i}^{\prime} \boldsymbol{\beta}+\varepsilon_{i}, \quad \text { with } \quad \varepsilon_{i} \mid \boldsymbol{x}_{i}, \boldsymbol{z}_{i} \sim N\left(0, \sigma^{2} \exp \left(\boldsymbol{z}_{i}^{\prime} \boldsymbol{\gamma}\right)\right)$$where $\boldsymbol{z}_{i}$ is a vector of regressors not including an intercept and $\boldsymbol{\theta}=\left(\boldsymbol{\beta}^{\prime}, \boldsymbol{\gamma}^{\prime}, \sigma^{2}\right)^{\prime}$ is th vector of unknown parameters.1. Write the first-order conditions for the maximum likelihood estimation of $\boldsymbol{\theta}$.2. Identify the set of restrictions that makes $V\left(\varepsilon_{i} \mid \boldsymbol{x}_{i}, \boldsymbol{z}_{i}\right)$ constant across observations.3. Write down the formulation of the LM test statistic for the null hypothesis corresponding to the above set of restrictions.

pset 5.2 Prove that $\hat{\boldsymbol{\beta}}_{G I V E}$ can be derived as the OLS estimator of $\boldsymbol{\beta}$ in the linear regression model$$\boldsymbol{y}=X \boldsymbol{\beta}+\hat{U} \boldsymbol{\gamma}+\boldsymbol{\eta}$$where $\hat{U}$ is the matrix of first-stage residuals.

pset 6.1 Prove that the OLS estimator of $\boldsymbol{\beta}$ in the linear regression model with individualspecific intercepts, that is$$y_{i t}=\boldsymbol{x}_{i t}^{\prime} \boldsymbol{\beta}+\alpha_{i}+u_{i t},$$where $\alpha_{i}$ is a parameter to be estimated, for $i=1, \ldots, n$ is equal to $\hat{\boldsymbol{\beta}}_{W G}$.

Consider the simplified classical normal linear regression problem written in matrix notation:y = Xβ + u, u ∼ N (0, σ 2 I n ), β ∈ R K , σ > 0,where y is an n-vector of endogenous variables, and X is a n × k matrix of regressors. Under whatcondition(s) is the parameter β point-identified in this model? Explain

Question 23Is the assumption of constant error variance (homoskedasticity) valid for Model 2? (Yes / No)

1/1

Upgrade your grade with Knowee

Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.