A growing farming conglomerate increases its water usage at a rate of 10% every year. If it used 13,000 megaliters of water this year, then how much water will it use 17 years from now?If necessary, round your answer to the nearest hundredth.

To solve this problem, we need to use the formula for compound interest, which is also applicable to any situation involving growth at a constant rate. The formula is:

A = P(1 + r/n)^(nt)

where:

• A is the amount of water used after n years,
• P is the initial amount of water used,
• r is the rate of increase,
• n is the number of times the increase is applied per time period, and
• t is the time the money is invested or borrowed for, in years.

In this case, the initial amount of water used (P) is 13,000 megaliters, the rate of increase (r) is 10% or 0.10, the increase is applied once per year (n = 1), and we want to find out the amount of water used after 17 years (t = 17).

Substituting these values into the formula, we get:

A = 13000(1 + 0.10/1)^(1*17)

Solving this equation will give us the amount of water used after 17 years.

Let's calculate it:

A = 13000 * (1 + 0.10)^17 A = 13000 * (1.10)^17 A = 13000 * 5.08986 A = 66128.18 megaliters

So, the farming conglomerate will use approximately 66128.18 megaliters of water 17 years from now, rounded to the nearest hundredth.