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A vendor sells 60 percent of apples he had and throws away 15 percent of the remainder. Next day he sells 50 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw?Options17%77%None23%

Question

A vendor sells 60 percent of apples he had and throws away 15 percent of the remainder. Next day he sells 50 percent of the remainder and throws away the rest. What percent of his apples does the vendor throw?Options17%77%None23%

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Solution

Sure, let's break it down:

  1. The vendor sells 60% of his apples, which means he has 40% of his apples left.

  2. He throws away 15% of the remaining 40%. To find out how much this is, we multiply 0.15 by 0.40 (15% of 40%), which gives us 0.06 or 6%. So now he has 34% of his apples left (40% - 6%).

  3. The next day, he sells 50% of the remaining 34%. To find out how much this is, we multiply 0.50 by 0.34 (50% of 34%), which gives us 0.17 or 17%. So now he has 17% of his apples left (34% - 17%).

  4. He throws away the rest, which is 17%.

So, the vendor throws away 6% of his apples on the first day and 17% of his apples on the second day. To find the total percentage of apples he throws away, we add these two percentages together: 6% + 17% = 23%.

Therefore, the vendor throws away 23% of his apples.

This problem has been solved

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