How many different 4 digit numbers can be formed using the digits 1, 2, 5, 6, 7 and 8?Options12024720360

The question is asking for the number of different 4-digit numbers that can be formed using the digits 1, 2, 5, 6, 7, and 8.

Here are the steps to solve this problem:

1. We have 6 different digits and we need to form a 4-digit number.

2. The first digit can be any of the 6 digits. So, we have 6 options for the first digit.

3. The second digit can be any of the remaining 5 digits (since we can't repeat a digit). So, we have 5 options for the second digit.

4. Similarly, the third digit can be any of the remaining 4 digits, giving us 4 options.

5. Finally, the fourth digit can be any of the remaining 3 digits, giving us 3 options.

6. To find the total number of 4-digit numbers, we multiply the number of options for each digit together.

So, the total number of different 4-digit numbers is 6 * 5 * 4 * 3 = 360.

Therefore, the answer is 360.