Two identical heaters 240 V, 1000 W are connected in series across a supply of 240 V line, then the combined power is:

Are household appliances connected in series or in parallel? How do you know? Why is this thestandard connection?

Two conducting wires of the same material and of equal lengths and equal diameters are first connected in series and then parallel in a circuit across the same potential difference. The ratio of heat produced in series and parallel combinations would be :(a) 1 : 2(b) 2 : 1(c) 1 : 4(d) 4 : 1

The power of the heater is 750 W750 W at 1000∘ C1000° C. What will be its power at 200∘ C200° C if thermal coefficient of resistance is α=4×10−4 °C−1𝛼=4×10-4 °C-1?

A heater is designed to operate with a power of 1000 W in a 100 V line. It is connected, in combination with a resistance of 10 Ω and a resistance R to a 100V line as shown in figure. What should be the value of R so that the heater operates with a power of 62.5 W?

A single phase voltage source Vs =240∠0° V RMS supplies two loads in parallel with thefollowing parameters (all values RMS),1) 10 kVA at a 0.6 lagging power factor2) 2 kW at a 0.90 leading power factora) Draw the power triangle for each of the two loads and complete Table 1. [4]b) Calculate the power triangle of the combined loads and complete Table 1. Draw thecombined power triangle. [2]c) Apply S=VsI s* to the combined power to calculate the phasor current I s.[1]d) Calculate the required kVARs of capacitance in parallel with the loads to correct the powerfactor to 0.9 lagging. Complete Table 1 as required. [2]e) Calculate the new phasor current I sn for the new power factor corrected system.