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1 and 8 are the first two natural numbers for which 1 + 2 + 3 + ... + n is a perfect square. Whichnumber is the 4th such number?

Question

1 and 8 are the first two natural numbers for which 1 + 2 + 3 + ... + n is a perfect square. Whichnumber is the 4th such number?

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Similar Questions

If it is possible to make a three-digit number, which is a perfect square of a two-digit number from the second, the fourth and the eight digits of 31792056, using each digit only once, what is the two-digit number? If the perfect square cannot be formed, your answer is ‘N’ and if more than one such numbers can be formed, your answer is ‘X’

Select the correct answerWhich one of the following can't be the square of natural number ?Options3097628561None of these14364275625

What is the smallest four-digit number that is a perfect square?a1 004 b1 016c1 024 d1 036

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Which of the following is not a perfect square?(171)8(14,641)8(61)8(57)8

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