Which of the following is not a method to append the list n_row=[1,2,3] as a new row to the dataframe df?df.iloc[len(df.index)]=n_rowdf.loc[len(df.index)]=n_rowdf.loc[-1]=n_rowdf.loc[len(df.index)]=n_row
Question
Which of the following is not a method to append the list n_row=[1,2,3] as a new row to the dataframe df?df.iloc[len(df.index)]=n_rowdf.loc[len(df.index)]=n_rowdf.loc[-1]=n_rowdf.loc[len(df.index)]=n_row
Solution
The method that is not used to append the list n_row=[1,2,3] as a new row to the dataframe df is df.loc[-1]=n_row.
This is because the .loc indexer is label-based, which means that you have to specify rows and columns based on their row and column labels. -1 is not a label that exists in the dataframe, so trying to use it to append a row will result in an error.
The other three methods, df.iloc[len(df.index)]=n_row, df.loc[len(df.index)]=n_row, and df.loc[len(df.index)]=n_row, are all valid ways to append a new row to a dataframe in pandas. They all work by specifying a new row label (which is the length of the dataframe's index, i.e., the next row number after the last one in the dataframe) and setting it equal to the list n_row.
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