Match List - I with List - II.List-I (Reactants) (A) Phenol, Zn/Δ(B) Phenol, CHCl3,NaOH,HCl(C) Phenol, CO2,NaOH,HCl(D) Phenol, Conc. HNO3List-II Products (I) Salicylaldehyde (II) Salicylic acid (III) Benzene (IV) Picric acid Choose the correct answer from the options given below.(A)-(IV), (B), (II), (C)-(I), (D)-(III)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)(A)-(III), (B)-(I), (C)-(II), (D)-(IV)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Question
Match List - I with List - II.List-I (Reactants) (A) Phenol, Zn/Δ(B) Phenol, CHCl3,NaOH,HCl(C) Phenol, CO2,NaOH,HCl(D) Phenol, Conc. HNO3List-II Products (I) Salicylaldehyde (II) Salicylic acid (III) Benzene (IV) Picric acid Choose the correct answer from the options given below.(A)-(IV), (B), (II), (C)-(I), (D)-(III)(A)-(IV), (B)-(I), (C)-(II), (D)-(III)(A)-(III), (B)-(I), (C)-(II), (D)-(IV)(A)-(III), (B)-(IV), (C)-(I), (D)-(II)
Solution
The correct answer is (A)-(III), (B)-(I), (C)-(II), (D)-(IV).
Here's why:
(A) Phenol, Zn/Δ: This reaction is a reduction process that converts phenol to benzene. So, (A) matches with (III).
(B) Phenol, CHCl3, NaOH, HCl: This is the Reimer-Tiemann reaction, which converts phenol to salicylaldehyde. So, (B) matches with (I).
(C) Phenol, CO2, NaOH, HCl: This is the Kolbe-Schmitt reaction, which converts phenol to salicylic acid. So, (C) matches with (II).
(D) Phenol, Conc. HNO3: This reaction is a nitration process that converts phenol to picric acid. So, (D) matches with (IV).
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