A nucleus of mass M emits γ-ray photon of frequency ν. The loss of internal energy by the nucleus is :Take c as the speed of electromagnetic wave
Question
A nucleus of mass M emits γ-ray photon of frequency ν. The loss of internal energy by the nucleus is :Take c as the speed of electromagnetic wave
Solution
The loss of internal energy by the nucleus can be calculated using the formula for the energy of a photon, which is given by E = hν, where h is Planck's constant and ν is the frequency of the photon.
Step 1: Identify the given values. The frequency of the photon (ν) is given in the problem. The value of Planck's constant (h) is a known constant, approximately 6.63 x 10^-34 Joule seconds.
Step 2: Substitute the given values into the formula. E = hν Substitute the given frequency and the value of Planck's constant into the formula.
Step 3: Calculate the energy. Multiply the frequency by Planck's constant to find the energy of the photon. This energy is the loss of internal energy by the nucleus, as it is the energy carried away by the emitted photon.
So, the loss of internal energy by the nucleus is hν.
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