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Given a positive integer denoting , do the following:If , print the lowercase English word corresponding to the number (e.g., one for , two for , etc.).If , print Greater than 9.Input FormatThe first line contains a single integer, .ConstraintsOutput FormatIf , then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input5Sample OutputfiveSample Input #018Sample Output #01eightSample Input #0244Sample Output #02Greater than 9

Question

Given a positive integer denoting , do the following:If , print the lowercase English word corresponding to the number (e.g., one for , two for , etc.).If , print Greater than 9.Input FormatThe first line contains a single integer, .ConstraintsOutput FormatIf , then print the lowercase English word corresponding to the number (e.g., one for , two for , etc.); otherwise, print Greater than 9 instead.Sample Input5Sample OutputfiveSample Input #018Sample Output #01eightSample Input #0244Sample Output #02Greater than 9

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Solution

This problem is asking for a program that will take an integer as input and output the English word for that number if it is less than or equal to 9. If the number is greater than 9, the program should output "Greater than 9".

Here is a step-by-step solution in Python:

  1. First, we need to create a list of English words for the numbers 1 to 9. We can do this with a list like this: num_words = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]

  2. Next, we need to take an integer as input. We can do this with the input() function in Python, and we can convert the input to an integer with the int() function. Like this: n = int(input())

  3. Now we need to check if the number is less than or equal to 9. We can do this with an if statement: if n <= 9:

  4. If the number is less than or equal to 9, we want to print the English word for that number. We can do this by indexing into our list of number words with n - 1 (since list indices start at 0 in Python). Like this: print(num_words[n - 1])

  5. If the number is greater than 9, we want to print "Greater than 9". We can do this with an else statement: else: print("Greater than 9")

Here is the complete program:

num_words = ["one", "two", "three", "four", "five", "six", "seven", "eight", "nine"]
n = int(input())
if n <= 9:
    print(num_words[n - 1])
else:
    print("Greater than 9")

This program will take an integer as input and print the English word for that number if it is less than or equal to 9, or "Greater than 9" if it is greater than 9.

This problem has been solved

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