When a baseball is hit, its height h (in meters) above the ground t seconds after being hit is given byht=−5t2+3​0t+1

h=−4.9t 2 +25tThe equation above expresses the approximate height ℎ, in meters, of a ball 𝑡𝑡 seconds after it is launched vertically upward from the ground with an initial velocity of 25 meters per second. After approximately how many seconds will the ball hit the ground?A3.5B4.0C4.5D5.0

When a baseball is hit, its height h (in meters) above the ground t seconds after being hit is given byht=−5t2+3​0t+1Use your GDC to graph the parabola. There are two x-intercepts. Find the coordinates of the leftmost x-intercept.

Jen served the final point before winning her tennis match! She tossed the ball up into the air from a height of 5 feet with a velocity of 22 feet per second. After the ball started to come back down, Jen hit the ball with her racket at a height of 6 feet.Which equation can you use to find how many seconds the ball was in the air before Jen hit it?If an object travels upward at a velocity of v feet per second from s feet above the ground, the object's height in feet, h, after t seconds can be modeled by the formula h=–16t2+vt+s.6=–16t2+22t+55=–16t2+22t+6To the nearest tenth of a second, how long was the ball in the air before Jen hit it? seconds

A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function =ht−80t16t2. After how long will it reach its maximum height?Do not round your answer.

(a)The function 𝑓(𝑡)=−5𝑡2+20𝑡+60f\left(t\right)=-5t^2+20t+60f(t)=−5t 2 +20t+60 models the approximate height of an object 𝑡tt seconds after it is launched. How many seconds does it take the object to hit the ground? (Enter only the number)