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Select the correct answerA person bought some articles at the rate of 5 per rupee and the same number at the rate of 4 per rupee. He mixed both' the types and sold at the rate of 9 for 2 rupees. In this business he suffered a loss of Rs. 3. The total number of articles bought by him was?Options10801090540545

Question

Select the correct answerA person bought some articles at the rate of 5 per rupee and the same number at the rate of 4 per rupee. He mixed both' the types and sold at the rate of 9 for 2 rupees. In this business he suffered a loss of Rs. 3. The total number of articles bought by him was?Options10801090540545

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Solution

The problem can be solved by using the concept of weighted average.

Let's denote:

  • the price of the first type of articles as P1 = 1/5 = 0.2 rupees/article,
  • the price of the second type of articles as P2 = 1/4 = 0.25 rupees/article,
  • the selling price as Ps = 2/9 ≈ 0.222 rupees/article,
  • the number of articles of each type as N,
  • the total cost as C = N * (P1 + P2),
  • the total revenue as R = 2N * Ps,
  • the loss as L = 3 rupees.

From the problem, we know that the total cost is greater than the total revenue by the loss, so we can write the equation:

C = R + L.

Substituting the known values, we get:

N * (0.2 + 0.25) = 2N * 0.222 + 3.

Solving this equation for N, we find:

N = 3 / (0.2 + 0.25 - 2*0.222) = 300.

Since the total number of articles is 2N (N of the first type and N of the second type), the answer is 2*300 = 600.

So, none of the options provided in the question is correct. The total number of articles bought by the person should be 600.

This problem has been solved

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