A body of mass 3 kg hits a wall at an angle of 60° and returns at the same angle. The impact time was 0.2 s. Calculate the force exerted on the wall :–150 N50 N100 N75 N
Question
A body of mass 3 kg hits a wall at an angle of 60° and returns at the same angle. The impact time was 0.2 s. Calculate the force exerted on the wall :–150 N50 N100 N75 N
Solution
To solve this problem, we need to use the law of conservation of momentum and the definition of force.
Step 1: Calculate the initial and final momentum
The initial momentum (p_initial) of the body is given by the product of its mass (m) and its initial velocity (v_initial). The final momentum (p_final) is given by the product of its mass and its final velocity (v_final).
However, since the body returns at the same angle, the final velocity is equal in magnitude but opposite in direction to the initial velocity. Therefore, the final momentum is -p_initial.
Step 2: Calculate the change in momentum
The change in momentum (Δp) is given by the final momentum minus the initial momentum. In this case, Δp = -p_initial - p_initial = -2p_initial.
Step 3: Calculate the force
The force (F) exerted on the wall is given by the change in momentum divided by the time it takes for the change to occur (t). Therefore, F = Δp / t.
Since we don't have the values of the initial or final velocities, we can't calculate the exact value of the force. However, we can say that the force is directed towards the wall (since the change in momentum is negative) and its magnitude is twice the magnitude of the initial momentum divided by the time of impact.
Without the values of the velocities, we can't determine which of the given options is correct.
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