This problem is asking you to find the sum of the XOR operation on all pairs of elements in an array.

Here is a step-by-step solution:

1. Initialize a variable `sum` to 0. This will hold the sum of all XOR operations.

2. Loop through the array. For each element, perform the XOR operation with every other element in the array.

3. Add the result of each XOR operation to `sum`.

4. After all pairs have been processed, print the value of `sum`.

Here is a Python solution for the problem:

```python
T = int(input())
for _ in range(T):
N = int(input())
arr = list(map(int, input().split()))
sum = 0
for i in range(N):
for j in range(i+1, N):
sum += arr[i] ^ arr[j]
print(sum)
```

This solution works by iterating over each pair of elements in the array only once (since `a XOR b` is the same as `b XOR a`), and adding the result of the XOR operation to the sum.

In the example provided, the sum of all XOR operations for the first test case is 52, and for the second test case is 60680.

Question

This problem is asking you to find the sum of the XOR operation on all pairs of elements in an array.

Here is a step-by-step solution:

1. Initialize a variable `sum` to 0. This will hold the sum of all XOR operations.

2. Loop through the array. For each element, perform the XOR operation with every other element in the array.

3. Add the result of each XOR operation to `sum`.

4. After all pairs have been processed, print the value of `sum`.

Here is a Python solution for the problem:

```python
T = int(input())
for _ in range(T):
    N = int(input())
    arr = list(map(int, input().split()))
    sum = 0
    for i in range(N):
        for j in range(i+1, N):
            sum += arr[i] ^ arr[j]
    print(sum)
```

This solution works by iterating over each pair of elements in the array only once (since `a XOR b` is the same as `b XOR a`), and adding the result of the XOR operation to the sum.

In the example provided, the sum of all XOR operations for the first test case is 52, and for the second test case is 60680.

Knowee AI · Accepted Answer