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An experiment consists of four outcomes with P(E1) = 0.2, P(E2) = 0.3, and P(E3) = 0.4. The probability of outcome E4 isQuestion 10Select one:a.0.1000b.0.1250c.0.010d.0.0250

Question

An experiment consists of four outcomes with P(E1) = 0.2, P(E2) = 0.3, and P(E3) = 0.4. The probability of outcome E4 isQuestion 10Select one:a.0.1000b.0.1250c.0.010d.0.0250

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Solution

The probability of an event is a measure of the likelihood that the event will occur. In a probability model, the sum of the probabilities of all possible outcomes is always equal to 1.

Given that P(E1) = 0.2, P(E2) = 0.3, and P(E3) = 0.4, we can find the probability of outcome E4 by subtracting the sum of P(E1), P(E2), and P(E3) from 1.

So, P(E4) = 1 - (P(E1) + P(E2) + P(E3)) = 1 - (0.2 + 0.3 + 0.4) = 1 - 0.9 = 0.1

Therefore, the probability of outcome E4 is 0.1 or 0.1000 in decimal form. So, the correct answer is a. 0.1000.

This problem has been solved

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