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You're developing a Bash script that reads lines from a text file. If a line contains the word "error," the script should display an error message and continue reading the next line. If a line contains the word "success," it should display a success message and break out of the loop. For all other lines, it should display a generic message. Which code snippet correctly implements this behavior using a while loop?1.0 Markswhile IFS= read -r line; doif [[ "$line" =~ "error" ]]; thenecho "Error: $line"elif [[ "$line" =~ "success" ]]; thenecho "Success: $line"breakelseecho "Info: $line"fidone < file.txtwhile read -r line; doif [[ "$line" == *"error"* ]]; thenecho "Error: $line"elif [[ "$line" == *"success"* ]]; thenecho "Success: $line"breakelseecho "Info: $line"fidone < file.txtwhile read -r line; doif [[ "$line" =~ "error" ]]; thenecho "Error: $line"elif [[ "$line" =~ "success" ]]; thenecho "Success: $line"breakelseecho "Info: $line"fidone < file.txtwhile IFS= read -r line; doif [[ "$line" == *error* ]]; thenecho "Error: $line"elif [[ "$line" == *success* ]]; thenecho "Success: $line"breakelseecho "Info: $line"fidone < file.txt

Question

You're developing a Bash script that reads lines from a text file. If a line contains the word "error," the script should display an error message and continue reading the next line. If a line contains the word "success," it should display a success message and break out of the loop. For all other lines, it should display a generic message. Which code snippet correctly implements this behavior using a while loop?1.0 Markswhile IFS= read -r line; doif [[ "line"= "error"]];thenecho"Error:line" =~ "error" ]]; thenecho "Error: line"elif [[ "line"= "success"]];thenecho"Success:line" =~ "success" ]]; thenecho "Success: line"breakelseecho "Info: line"fidone<file.txtwhilereadrline;doif[["line"fidone < file.txtwhile read -r line; doif [[ "line" == "error" ]]; thenecho "Error: line"elif[["line"elif [[ "line" == "success" ]]; thenecho "Success: line"breakelseecho"Info:line"breakelseecho "Info: line"fidone < file.txtwhile read -r line; doif [[ "line"= "error"]];thenecho"Error:line" =~ "error" ]]; thenecho "Error: line"elif [[ "line"= "success"]];thenecho"Success:line" =~ "success" ]]; thenecho "Success: line"breakelseecho "Info: line"fidone<file.txtwhileIFS=readrline;doif[["line"fidone < file.txtwhile IFS= read -r line; doif [[ "line" == error ]]; thenecho "Error: line"elif[["line"elif [[ "line" == success ]]; thenecho "Success: line"breakelseecho"Info:line"breakelseecho "Info: line"fidone < file.txt

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Solution

The correct code snippet that implements the desired behavior using a while loop in Bash is:

while read -r line; do
    if [[ "$line" == *"error"* ]]; then
        echo "Error: $line"
    elif [[ "$line" == *"success"* ]]; then
        echo "Success: $line"
        break
    else
        echo "Info: $line"
    fi
done < file.txt

This script reads the file line by line. If a line contains the word "error", it prints an error message. If a line contains the word "success", it prints a success message and breaks the loop. For all other lines, it prints a generic message. The * before and after "error" and "success" in the condition of the if and elif statements is used to match any line that contains these words, regardless of what comes before or after them.

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