If u=sin-1(𝒙𝟐􀬾𝒚𝟐 𝒙􀬾𝒚 ), then prove that (i) x𝝏𝒖 𝝏𝒙 + 𝒚 𝝏𝒖 𝝏𝒚 =tanu and (ii) x2𝝏𝟐𝒖 𝝏𝒙𝟐 +𝟐𝒙𝒚 𝝏𝟐𝒖 𝝏𝒙𝝏𝒚 𝒚𝟐 𝝏𝟐𝒈 𝝏𝒚𝟐= tan3u

Verify the identity.cos(u) sec(u)tan(u) = cot(u)Use a Reciprocal Identity to rewrite the expression, and then simplify.cos(u) sec(u)tan(u) =  cos(u) sec(u)   =  cos(u) · 1cos(u) ·   =

Prove the trigonometric identity 𝑐𝑜𝑠2𝐴 + 𝑠𝑖𝑛2𝐴 = 1

Given 𝛼 = tan−1 𝑥, find the exact values of sin 𝛼 and cos 𝛼

𝜕𝜕𝑥 (2 tan−1 (𝑦𝑥))

Rewrite tansin−1u6 as an algebraic expression in u.=tansin−1u6