Suppose a hash table of size 10 uses linear probing for collision resolution and key%10 as hash function. If the key values that are hashed are as follows: {23, 55, 42, 3, 12} , what is the location of 12? a.2b.3c.4d.5e.None of These
Question
Suppose a hash table of size 10 uses linear probing for collision resolution and key%10 as hash function. If the key values that are hashed are as follows: {23, 55, 42, 3, 12} , what is the location of 12? a.2b.3c.4d.5e.None of These
Solution
The hash function is key%10. This means we calculate the remainder when the key is divided by 10.
Step 1: Calculate the hash value for 12 using the hash function. 12 % 10 = 2.
So, the initial location for 12 in the hash table is 2.
Step 2: Check if there is a collision at this location.
The keys 23, 55, 42, and 3 have already been hashed. Their hash values are:
23 % 10 = 3 55 % 10 = 5 42 % 10 = 2 3 % 10 = 3
So, there is a collision at location 2 because the key 42 is already stored there.
Step 3: Resolve the collision using linear probing.
In linear probing, we move to the next available slot in the hash table when there is a collision.
The next available slot after 2 is 3, but it is occupied by the key 23. So, we move to the next slot, which is 4.
Therefore, the location of 12 in the hash table is 4.
So, the answer is c. 4.
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