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Two small spheres with charges q1 and q2 are 20 cm apart.  A third sphere with a charge of −2.0 nC is placed directly between them.If the sphere with charge q2 experiences a zero net electric force, what is the value of q1?A.−8 nCB.4 nCC.8 nCD.16 nC

Question

Two small spheres with charges q1 and q2 are 20 cm apart.  A third sphere with a charge of −2.0 nC is placed directly between them.If the sphere with charge q2 experiences a zero net electric force, what is the value of q1?A.−8 nCB.4 nCC.8 nCD.16 nC

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Solution

To solve this problem, we need to use Coulomb's Law, which states that the force between two charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. The formula is F = k * |q1*q2| / r^2, where F is the force, k is Coulomb's constant, q1 and q2 are the charges, and r is the distance between the charges.

Given that the sphere with charge q2 experiences a zero net electric force, the forces exerted on it by the other two spheres must cancel each other out. This means that the force exerted by the sphere with charge q1 must be equal in magnitude and opposite in direction to the force exerted by the sphere with charge -2.0 nC.

Let's denote the distance between the sphere with charge q1 and the sphere with charge q2 as d. Since the third sphere is placed directly between them, the distance from the sphere with charge q1 to the third sphere is d/2, and the distance from the third sphere to the sphere with charge q2 is also d/2.

Setting the magnitudes of the two forces equal to each other, we get:

k * |q1*(-2.0 nC)| / (d/2)^2 = k * |q2*(-2.0 nC)| / (d/2)^2

Solving for q1, we get:

q1 = q2

Since q2 is experiencing a zero net electric force, its charge must be equal to the charge of the third sphere, which is -2.0 nC. Therefore, q1 must also be -2.0 nC.

So, the correct answer is A.−8 nC.

This problem has been solved

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