Sure, here are the steps to factorise the expression x^2 - 6x + 9:

1. Identify the expression: The expression given is a quadratic expression, which is in the form of ax^2 + bx + c. Here, a = 1, b = -6, and c = 9.

2. Look for perfect squares: In this case, x^2 is the square of x, and 9 is the square of 3.

3. Check if 2*sqrt(a)*sqrt(c) equals to b: Here, 2*sqrt(1)*sqrt(9) equals to 2*1*3 = 6, which is the absolute value of b (-6).

4. Since all conditions for a perfect square trinomial are satisfied, the expression can be written as (sqrt(a)x - sqrt(c))^2.

5. Therefore, the factorised form of the expression x^2 - 6x + 9 is (x - 3)^2.

Question

Sure, here are the steps to factorise the expression x^2 - 6x + 9:

1. Identify the expression: The expression given is a quadratic expression, which is in the form of ax^2 + bx + c. Here, a = 1, b = -6, and c = 9.

2. Look for perfect squares: In this case, x^2 is the square of x, and 9 is the square of 3.

3. Check if 2*sqrt(a)*sqrt(c) equals to b: Here, 2*sqrt(1)*sqrt(9) equals to 2*1*3 = 6, which is the absolute value of b (-6).

4. Since all conditions for a perfect square trinomial are satisfied, the expression can be written as (sqrt(a)x - sqrt(c))^2.

5. Therefore, the factorised form of the expression x^2 - 6x + 9 is (x - 3)^2.

Knowee AI · Accepted Answer

Sure, here are the steps to factorise the expression x^2 - 6x + 9:

1. Identify the expression: The expression given is a quadratic expression, which is in the form of ax^2 + bx + c. Here, a = 1, b = -6, and c = 9.

2. Look for perfect squares: In this case, x^2 is the square of x, and 9 is the square of 3.

3. Check if 2*sqrt(a)*sqrt(c) equals to b: Here, 2*sqrt(1)*sqrt(9) equals to 2*1*3 = 6, which is the absolute value of b (-6).

4. Since all conditions for a perfect square trinomial are satisfied, the expression can be written as (sqrt(a)x - sqrt(c))^2.

5. Therefore, the factorised form of the expression x^2 - 6x + 9 is (x - 3)^2.

Factorise the expression x 2 −6x+9.