Two years ago a father was four times as old as his son. Three years from now the father will be only three times as old as the son. How old is each now?If x represents the son's age two years ago, which expression represents his father's age three years from now?3x + 33x + 15x + 3

Let's solve the problem step by step:

1. Let's assume the son's current age is represented by "x".
2. Two years ago, the son's age would have been "x - 2".
3. According to the problem, two years ago, the father was four times as old as his son. So, the father's age two years ago would have been "4(x - 2)".
4. Now, let's find the current age of the father. Since two years have passed, the father's current age would be "4(x - 2) + 2".
5. According to the problem, three years from now, the father will be three times as old as the son. So, the father's age three years from now would be "3(x + 3)".
6. To find the current ages of the son and the father, we need to solve the equation: "4(x - 2) + 2 = 3(x + 3)".

Now, let's solve the equation:

4(x - 2) + 2 = 3(x + 3) 4x - 8 + 2 = 3x + 9 4x - 6 = 3x + 9 4x - 3x = 9 + 6 x = 15

Therefore, the son's current age is 15 years old.

To find the father's current age, we substitute the value of x into the expression we found earlier:

Father's age three years from now = 3(x + 3) Father's age three years from now = 3(15 + 3) Father's age three years from now = 3(18) Father's age three years from now = 54

Therefore, the father's current age is 54 years old.