The population of a town is 10,000. If the population of males increases by 16.66% and that of the female by 37.5%, the population becomes 12,500. Find the number of females.6000500040003000
Question
The population of a town is 10,000. If the population of males increases by 16.66% and that of the female by 37.5%, the population becomes 12,500. Find the number of females.6000500040003000
Solution
To solve this problem, we need to set up a system of equations.
Let's denote the number of males in the town as M and the number of females as F. We know from the problem that:
M + F = 10,000 (This is the total population of the town)
We also know that the population of males increases by 16.66% and the population of females increases by 37.5%, resulting in a new total population of 12,500. This gives us a second equation:
1.1666M + 1.375F = 12,500
Now we have a system of two equations, and we can solve it step by step.
First, let's express M from the first equation:
M = 10,000 - F
Now we can substitute M in the second equation:
1.1666(10,000 - F) + 1.375F = 12,500
This simplifies to:
11666 - 1.1666F + 1.375F = 12,500
Combine like terms:
0.2084F = 834
Finally, solve for F:
F = 834 / 0.2084 ≈ 4000
So, the number of females in the town is approximately 4000.
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