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d) A solid weighs 32 gf in air and 28.8 gf in water. Calculate the relative density of the solid.

Question

d) A solid weighs 32 gf in air and 28.8 gf in water. Calculate the relative density of the solid.

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Solution

Step 1: First, we need to find the weight of the solid in air and in water. The weight of the solid in air is given as 32 gf and in water as 28.8 gf.

Step 2: The loss of weight in water is the difference between the weight of the solid in air and in water. So, we subtract the weight in water from the weight in air: 32 gf - 28.8 gf = 3.2 gf.

Step 3: The relative density (also known as specific gravity) of a substance is the ratio of the density of the substance to the density of a reference substance. In this case, the reference substance is water. The density of water is typically 1 g/cm³.

Step 4: The formula to calculate the relative density is: Relative Density = Weight in Air / Loss of Weight in Water.

Step 5: Substitute the given values into the formula: Relative Density = 32 gf / 3.2 gf = 10.

So, the relative density of the solid is 10.

This problem has been solved

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