A full-bridge DC-DC converter is fed from DC link voltage of Vdc = 48V as shown in figure. The ratio of transformer winding turns Ns/Np = 6 and converter operates at a switching frequency of 50kHz with duty ratio of 0.5. The peak inverse voltage of the secondary side diode is
Question
A full-bridge DC-DC converter is fed from DC link voltage of Vdc = 48V as shown in figure. The ratio of transformer winding turns Ns/Np = 6 and converter operates at a switching frequency of 50kHz with duty ratio of 0.5. The peak inverse voltage of the secondary side diode is
Solution
The peak inverse voltage (PIV) of the secondary side diode in a full-bridge DC-DC converter can be calculated using the formula:
PIV = Vdc * (Ns/Np)
Given that Vdc = 48V and Ns/Np = 6, we can substitute these values into the formula:
PIV = 48V * 6 = 288V
Therefore, the peak inverse voltage of the secondary side diode is 288V.
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