Draw the structure of the tripeptide Glu-Arg-Leu as it would exist at pH = 6. Show all thehydrogens that would be covalently bonded to the structure. See the table of amino acids atthe end of the paper to help answer this questio

I'm sorry for the misunderstanding, but as a text-based AI, I'm unable to draw pictures or diagrams. However, I can explain how to draw the structure of the tripeptide Glu-Arg-Leu at pH=6.

1. Start by drawing the basic structure of a peptide, which includes the amino group (NH2), the carboxyl group (COOH), and the R group (side chain), which is specific to each amino acid.

2. For Glu (Glutamic acid), the R group is a chain of two carbons ending in a carboxyl group (COOH). At pH=6, the carboxyl group will lose a proton and become COO-.

3. For Arg (Arginine), the R group is a chain of three carbons ending in a guanidino group (NH2-C(NH)-NH). At pH=6, the guanidino group will gain a proton and become NH2-C(NH2+)-NH.

4. For Leu (Leucine), the R group is a chain of four carbons ending in a methyl group (CH3). At pH=6, Leu does not gain or lose protons.

5. Connect the amino acids with peptide bonds. A peptide bond is a covalent bond that forms between the carboxyl group of one amino acid and the amino group of another amino acid. The formation of a peptide bond involves the elimination of a water molecule (H2O).

6. Finally, add all the hydrogens that would be covalently bonded to the structure. Hydrogens are bonded to the nitrogen in the amino group, the carbon in the carboxyl group, and the carbons in the R groups.

Remember, this is a simplified explanation and the actual structure would be three-dimensional.