What is the total number of moles of ions in 200 mL of 0.150 M Al2(SO4)3?

Sure, here are the steps to calculate the total number of moles of ions in 200 mL of 0.150 M Al2(SO4)3:

1. First, we need to find the number of moles of Al2(SO4)3. We can do this by using the formula for molarity (M), which is moles of solute/volume of solution in liters.

   So, moles of Al2(SO4)3 = Molarity * Volume in liters = 0.150 moles/L * 0.200 L = 0.030 moles of Al2(SO4)3

2. Next, we need to determine the number of ions in one formula unit of Al2(SO4)3. In one formula unit of Al2(SO4)3, there are 2 Al3+ ions and 3 SO4 2- ions.

3. Therefore, the total number of ions in one formula unit of Al2(SO4)3 is 2 + 3*4 = 14 ions (2 from Al and 12 from SO4).

4. Finally, we multiply the number of moles of Al2(SO4)3 by Avogadro's number (6.022 x 10^23) to get the number of formula units, and then multiply by the number of ions per formula unit to get the total number of ions.

   Total ions = moles of Al2(SO4)3 * Avogadro's number * ions per formula unit = 0.030 moles * 6.022 x 10^23 formula units/mole * 14 ions/formula unit = 2.52 x 10^24 ions

So, there are approximately 2.52 x 10^24 ions in 200 mL of 0.150 M Al2(SO4)3.