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Tim joined a book club to spend more quality time with his cousin. At the first meeting, club members recorded how many hours a week they typically read and whether they preferred e-readers or paperback books.E-readers Paperback booksAbout 1 hour per week 6 3About 3 hours per week 2 6What is the probability that a randomly selected club member reads about 1 hour per week and prefers paperback books?Simplify any fractions.

Question

Tim joined a book club to spend more quality time with his cousin. At the first meeting, club members recorded how many hours a week they typically read and whether they preferred e-readers or paperback books.E-readers Paperback booksAbout 1 hour per week 6 3About 3 hours per week 2 6What is the probability that a randomly selected club member reads about 1 hour per week and prefers paperback books?Simplify any fractions.

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Solution

To solve this problem, we first need to find the total number of club members. We do this by adding all the numbers in the table:

6 (e-readers, 1 hour) + 3 (paperback, 1 hour) + 2 (e-readers, 3 hours) + 6 (paperback, 3 hours) = 17 total members

Next, we find the number of members who read about 1 hour per week and prefer paperback books. According to the table, this is 3.

The probability of an event is calculated by dividing the number of ways the event can occur by the total number of outcomes. In this case, the event is a club member reading about 1 hour per week and preferring paperback books, and the total number of outcomes is the total number of club members.

So, the probability is 3 (members who read 1 hour per week and prefer paperback) divided by 17 (total members).

Therefore, the probability that a randomly selected club member reads about 1 hour per week and prefers paperback books is 3/17.

This problem has been solved

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