If 21.5 mol of Ne gas occupies 105.8 L, how many mol of Ne would occupy 549.8 L under the same temperature and pressure? Record your answer in scientific notation using 3 significant figures.

To solve this problem, we can use the ideal gas law equation, which states that the volume of a gas is directly proportional to the number of moles of the gas, assuming that temperature and pressure are constant.

Given that 21.5 mol of Ne gas occupies 105.8 L, we can set up a proportion to find out how many moles of Ne would occupy 549.8 L.

The proportion is as follows:

21.5 mol / 105.8 L = x mol / 549.8 L

To solve for x, we can cross-multiply and divide:

x = (21.5 mol * 549.8 L) / 105.8 L

After performing the calculation, we find that x = 111.5 mol.

However, the problem asks for the answer in scientific notation with three significant figures. In scientific notation, 111.5 is written as 1.115 * 10^2.

So, 549.8 L of Ne gas would contain approximately 1.12 * 10^2 mol of Ne under the same temperature and pressure.