In which of the following process highest energy is absorbed?Cu→Cu+Br→Br−I→I−Li→Li+
Question
In which of the following process highest energy is absorbed?Cu→Cu+Br→Br−I→I−Li→Li+
Solution
The process in which the highest energy is absorbed would be Li → Li+. This is because lithium (Li) is an alkali metal and it has only one electron in its outermost shell. When it loses that electron to become Li+, it requires a significant amount of energy to remove that electron. This is due to the strong attraction between the positively charged nucleus and the negatively charged electron.
On the other hand, transition metals like copper (Cu) and halogens like bromine (Br) and iodine (I) require less energy to gain or lose electrons because they have more than one electron in their outermost shell and the attraction between the nucleus and the outermost electrons is less strong.
Therefore, the process Li → Li+ absorbs the highest energy.
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