Find the linear transformation T : ℝ2 → ℝ2 that has the values given below on the given basis.T 2 1 = 4 6, T 1 1 = 3 7(a) First write a general vector v as a linear combination of the basis vectors.v =v1 v2 = v1−v2 2 1 + 2v2−v1 1 1(b) This implies the following.T(v) = T v1 v2= 4v1+3v2 6v1+7v2 = v
Question
Find the linear transformation T : ℝ2 → ℝ2 that has the values given below on the given basis.T 2 1 = 4 6, T 1 1 = 3 7(a) First write a general vector v as a linear combination of the basis vectors.v =v1 v2 = v1−v2 2 1 + 2v2−v1 1 1(b) This implies the following.T(v) = T v1 v2= 4v1+3v2 6v1+7v2 = v
Solution
The text you provided seems to be a mix of English and mathematical notation, but it's a bit unclear. However, I'll try to explain the process of finding a linear transformation based on the given values.
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We are given that T(2,1) = (4,6) and T(1,1) = (3,7). These are the images of the basis vectors under the transformation T.
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A general vector v in ℝ2 can be written as a linear combination of the basis vectors. So, we can write v = a(2,1) + b(1,1) for some scalars a and b.
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To find the image of v under the transformation T, we apply T to the linear combination. Because T is a linear transformation, we can distribute it over the sum and factor it out of the scalar multiples. So, T(v) = T(a(2,1) + b(1,1)) = aT(2,1) + bT(1,1).
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Substituting the given values of T(2,1) and T(1,1), we get T(v) = a(4,6) + b(3,7) = (4a + 3b, 6a + 7b).
So, the linear transformation T : ℝ2 → ℝ2 that has the given values on the given basis is T(v) = (4a + 3b, 6a + 7b), where v = a(2,1) + b(1,1).
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