If sin2 A = tan2 45°, where A is an acute angle, then the value of A is:
Question
If sin2 A = tan2 45°, where A is an acute angle, then the value of A is:
Solution
The given equation is sin²A = tan²45°.
We know that tan 45° = 1. So, the equation becomes sin²A = 1.
The square root of 1 is 1, so sin A = 1.
The angle whose sine is 1 is 90°. Therefore, A = 90°.
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